For f(x) = sqrt(x - 1), which condition must x satisfy?

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Multiple Choice

For f(x) = sqrt(x - 1), which condition must x satisfy?

Explanation:
The crucial idea is that a real square root is defined only when the expression inside the root is nonnegative. For f(x) = sqrt(x - 1), the radicand is x - 1, so we need x - 1 ≥ 0, which gives x ≥ 1. That means the function is defined for all x at least 1. Values smaller than 1 make the inside negative, so the square root would not be real. The other options fail because they don’t guarantee nonnegativity of the radicand.

The crucial idea is that a real square root is defined only when the expression inside the root is nonnegative. For f(x) = sqrt(x - 1), the radicand is x - 1, so we need x - 1 ≥ 0, which gives x ≥ 1. That means the function is defined for all x at least 1. Values smaller than 1 make the inside negative, so the square root would not be real. The other options fail because they don’t guarantee nonnegativity of the radicand.

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