If all A are B and all B are C, what can be concluded about A and C?

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Multiple Choice

If all A are B and all B are C, what can be concluded about A and C?

Explanation:
Transitive inclusion in sets: if every A is inside B and every B is inside C, then every A is inside C. This happens because any element that is in A must be in B, and since that element is also in B, it is in C as well. So the conclusion is that all A are C. The other options don’t follow from the chain: saying no A are C contradicts the established containment, and simply restating that all A are B is weaker than the deduced all A are C, while “cannot determine” ignores the transitive link given.

Transitive inclusion in sets: if every A is inside B and every B is inside C, then every A is inside C. This happens because any element that is in A must be in B, and since that element is also in B, it is in C as well. So the conclusion is that all A are C. The other options don’t follow from the chain: saying no A are C contradicts the established containment, and simply restating that all A are B is weaker than the deduced all A are C, while “cannot determine” ignores the transitive link given.

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