Under F = m*a, if mass doubles while acceleration remains constant, what happens to the force?

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Multiple Choice

Under F = m*a, if mass doubles while acceleration remains constant, what happens to the force?

Explanation:
Force is directly proportional to mass when acceleration is fixed. According to F = m*a, if you keep a the same and double the mass, the force becomes F2 = (2m)*a = 2*(m*a) = 2F. So doubling the mass with constant acceleration requires doubling the net force. Intuitively, a heavier object under the same acceleration needs twice as much push to maintain that rate of velocity change. The other options would only occur if the acceleration changed: halving the force would correspond to half the mass, keeping the force the same would imply the acceleration is halved, and quadrupling the force would require quadrupling the mass.

Force is directly proportional to mass when acceleration is fixed. According to F = ma, if you keep a the same and double the mass, the force becomes F2 = (2m)a = 2(ma) = 2F. So doubling the mass with constant acceleration requires doubling the net force. Intuitively, a heavier object under the same acceleration needs twice as much push to maintain that rate of velocity change. The other options would only occur if the acceleration changed: halving the force would correspond to half the mass, keeping the force the same would imply the acceleration is halved, and quadrupling the force would require quadrupling the mass.

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